- Jun 8, 2016
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The formula is exit speed=q*(pitch speed)+(1+q)*(bat speed) where q is 0.2 for wood bats, 0.5 for bbcor baseball bats and 1.15 for USSSA baseball bats. Couldn't find q numbers for softball. So the "better" the bat the faster it comes off (obviously) everything else being equal and yes the higher the q value the higher the percent of the exit velocity which will come from theI'm sure your calculations are correct with a wooden bat and a baseball. However I played baseball for a wooden bat league for MANY years before I started playing men's fast-pitch. The harder pitching, to be honest really only hurt the hands and broke more bats but the ball never really went much farther.
When I started playing mens fastpitch about 20 years ago (I still play) the biggest difference I felt was how fast the ball came off the composite bat. The slower the pitcher the less likely the ball was gonna leave the field, the faster the pitcher the more dingers and stingers we hit..... Like I said I'm sure your numbers are right but coming from someone who actually plays, I'm not sure I agree, respectfully of course.
pitch speed so your observations line up with that assuming the q is pretty high for fastpitch.
So a slight mea culpa from me..I was stuck in MLB
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